Collections UserString in Python
Strings are the arrays of bytes representing Unicode characters. However, Python does not support the character data type. A character is a string of length one.
Example:
Python3
# Python program to demonstrate# string# Creating a String # with single Quotes String1 = 'Welcome to the CodeConfig World'print("String with the use of Single Quotes: ") print(String1) # Creating a String # with double Quotes String1 = "I love coding"print("\nString with the use of Double Quotes: ") print(String1) |
Output:
String with the use of Single Quotes: Welcome to the CodeConfig World String with the use of Double Quotes: I love coding.
Note: For more information, refer to Python String
Collections.UserString
Python supports a String simillar as a container called UserString present in the collections module. This class acts when a wrapper class around the string objects. This class is useful when one wants to create a string of their own with some modified functionality or with some new functionality. It can be considered when a way of adding new behaviors for the string. This class takes any argument that can be converted to string and simulates a string whose content is kept in a regular string. The string is accessible by the data property of this class.
Syntax:
collections.UserString(seq)
Example 1:
Python3
# Python program to demonstrate# userstringfrom collections import UserStringd = 12344# Creating an UserDictuserS = UserString(d)print(userS.data)# Creating an empty UserDictuserS = UserString("")print(userS.data) |
Output:
12344
Example 2:
Python3
# Python program to demonstrate# userstring from collections import UserString # Creating a Mutable Stringclass Mystring(UserString): # Function to append to # string def append(self, s): self.data += s # Function to remove from # string def remove(self, s): self.data = self.data.replace(s, "") # Driver's codes1 = Mystring("Codes")print("Original String:", s1.data)# Appending to strings1.append("s")print("String After Appending:", s1.data)# Removing from strings1.remove("e")print("String after Removing:", s1.data) |
Output:
Original String: Codes String After Appending: Codess String after Removing: Codss